jQuery的:等到所有Ajax调用完成再继续 [英] jquery : wait until all ajax calls finish then continue
问题描述
我有我的document.ready一些Ajax调用()
I have some ajax calls in my document.ready()
这样的:
for (j=1; j <= 7; j++){
(function(index) {
$.getJSON('my.php', {id:index},
function(data) {
$.each(data, function(index2, array){
........
});
});
})(j)
}
//DO NOT CONTINUE UNTIL FINISH AJAX CALLS
........
MORE JQUERY CODE
我怎么能强制等待,而不是继续下去,直到我们得到了所有的回调从Ajax请求?
How can i force it to wait and not continue until we get all the call backs from the ajax requests ?
推荐答案
我不喜欢任何答案可言,(因为jQuery的1.5或更高版本)的最好方法是使用延迟的对象,那些对象来处理异步调用,您能解决:
I do not like any answer at all, the best way (since Jquery 1.5+) is to use Deferred objects, those are objects to manipulate async calls, you can solve :
$.when($.ajax("/page1.php"), $.ajax("/page2.php"))
.then(myFunc, myFailure);
2 Ajax调用后,此方法myFunc的执行,并myFailure如果任何人有一个错误。
This way myFunc executes after the 2 ajax calls are made, and myFailure if either one has an error.
您可以阅读更多关于它在jQuery的官方文档: JQuery的延迟的对象
You can read more about it in the jquery official documentation:JQuery Deferred Object
我写这篇文章的解决方案,如果有人看到这个帖子可能会有所帮助。
I write this solution if anyone sees this post it may be helpful.
对不起我的英语水平:P
Sorry my english :P
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