如何使手机振动从Qt Android [英] How to make phone vibrate from Qt Android

问题描述

我正在使用Qt部署Android应用程式。

我想让手机振动。因此，我尝试使用 QAndroidJniObject 执行此代码。

Java代码：

  import android.os.Vibrator; 
 Vibrator v =（Vibrator）this.context.getSystemService（Context.VIBRATOR_SERVICE）; 
 v.vibrate（500）; 
  

C ++ Qt代码：

  QAndroidJniObject activity = QAndroidJniObject :: callStaticObjectMethod（org / qtproject / qt5 / android / QtNative，activity，（）Landroid / app / Activity;）; 
 
 if（activity.isValid（））
 {
 QAndroidJniObject serviceName = QAndroidJniObject :: fromString（android.content.Context.VIBRATOR_SERVICE）; 
 if（serviceName.isValid（））
 {
 QAndroidJniObject vibrator = activity.callObjectMethod（getSystemService，（Ljava / lang / String;）Ljava / lang / Object;，serviceName .object< jobject>（））; 
 if（vibrator.isValid（））
 {
 vibrator.callMethod< void>（vibrate，（J）V，1000）; 
} 
 //振子实际上是无效的！ 
} 
} 
  

vibrator.isValid 返回false，我不知道为什么....这不是我第一次尝试这样的东西，但在这里，我不能让它工作。

注意：我的应用程式有 android.permission.VIBRATE 设定

解决方案

从我可以从收集的文档 a>， QAndroidJniObject :: fromString 返回一个包含Java字符串的对象，其中包含您给 fromString / p>

所以你现在做的就好像你在Java中做了下面这样：

  Object vibrator = getSystemService（Context.VIBRATOR_SERVICE）; 
  

当你真正想要的是：

  Object vibrator = getSystemService（Context.VIBRATOR_SERVICE）; 
 

所以不要使用 QAndroidJniObject :: fromString 你可能应该这样做：

  QAndroidJniObject serviceName = 
 QAndroidJniObject :: getStaticObjectField< jstring> b $ bandroid / content / Context，
VIBRATOR_SERVICE）; 
  

可能需要删除 serviceName 。

I'm deploying Android app using Qt.

I'd like to make the phone vibrate. So I try to execute this code using QAndroidJniObject.

Java code:

import android.os.Vibrator;
Vibrator v = (Vibrator) this.context.getSystemService(Context.VIBRATOR_SERVICE);
v.vibrate(500);

C++ Qt code:

QAndroidJniObject activity = QAndroidJniObject::callStaticObjectMethod("org/qtproject/qt5/android/QtNative", "activity", "()Landroid/app/Activity;");

if ( activity.isValid() )
{
    QAndroidJniObject serviceName = QAndroidJniObject::fromString("android.content.Context.VIBRATOR_SERVICE");
    if ( serviceName.isValid() )
    {
        QAndroidJniObject vibrator = activity.callObjectMethod("getSystemService", "(Ljava/lang/String;)Ljava/lang/Object;",serviceName.object<jobject>());
        if ( vibrator.isValid() )
        {
            vibrator.callMethod<void>("vibrate", "(J)V", 1000);
        }
        // vibrator is actually not valid!
    }
}

vibrator.isValid() returns false and I cannot figure out why....It's not my first time trying to do this kind of stuff, but here, I can't make it work.

Note: My app has android.permission.VIBRATE set

解决方案

From what I could gather from the documentation, QAndroidJniObject::fromString returns an object wrapping a Java string with the contents that you gave to fromString.

So what you're doing right now is as if you had done the following in Java:

Object vibrator = getSystemService("Context.VIBRATOR_SERVICE");

when what you really want is:

Object vibrator = getSystemService(Context.VIBRATOR_SERVICE);

So instead of using QAndroidJniObject::fromString you probably ought to be doing something like this:

QAndroidJniObject serviceName = 
    QAndroidJniObject::getStaticObjectField<jstring>(
        "android/content/Context",
        "VIBRATOR_SERVICE");

It's possible that you need to delete the local reference to serviceName afterwards.

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