HTTP错误414请求URL太长 [英] HTTP Error 414. The request URL is too long

问题描述

我使用ckeditor的格式化我的文本域里面的一些数据

I am using ckeditor to format some data inside my textarea

<textarea id="editorAbout" rows="70" cols="80" name="editorAbout"></textarea>

现在，当我尝试使用发布此数据 jQuery.ajax 这样，

Now when i try to post this data using jQuery.ajax like this,

var about=escape( $("#editorAbout").text());
            $.ajax({
             type: "POST",
             url: "../Allcammand.aspx?cmd=EditAboutCompany&about="+about,
             type:"post",
                async: false ,
                   success: function(response){                                       

                    },
                    error:function(xhr, ajaxOptions, thrownError){alert(xhr.responseText); }
            });

我得到的错误

I get the error

HTTP错误414请求URL太长。

HTTP Error 414. The request URL is too long.

我在这里得到的错误： http://iranfairco.com/example/errorLongUrl.aspx
试着点击修改文本按钮左下方的页面。

I am getting the error here: http://iranfairco.com/example/errorLongUrl.aspx
Try clicking on the Edit Text button at the bottom left of that page.

这是怎么回事？我该如何解决呢？

Why is this happening? How can I solve it?

推荐答案

据的这个问题 URL的最大实际长度为2000个字符。这不会是能容纳一个巨大的维基百科的文章一样，你要发送。

According to this question the maximum practical length of a URL is 2000 characters. This isn't going to be able to hold a massive Wikipedia article like you're trying to send.

。您需要添加一个数据价值，你传递给Ajax调用函数的对象。像这样的：

Instead of putting the data on the URL you should be putting it in the body of a POST request. You need to add a data value to the object you're passing to the ajax function call. Like this:

function editAbout(){

    var about=escape( $("#editorAbout").text());
    $.ajax({
        url: "Allcammand.aspx?cmd=EditAboutCompany&idCompany="+getParam("idCompany"),
        type:"post",
        async: false,
        data: {
            about: about
        },
        success: function(response){                                       
        },
        error:function(xhr, ajaxOptions, thrownError){alert(xhr.responseText); ShowMessage("??? ?? ?????? ??????? ????","fail");}
    });
}

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