捕捉到的网页有userscript XMLHTTP请求 [英] capture a pages xmlhttp requests with a userscript

问题描述

我有，增加了显著的功能到一个页面，但最近被打破，因为开发商增加了一些AJAX到该页面的用户脚本（镀铬和FF）。我想修改脚本听页面XMLHTTP请求，这样我可以动态地更新我添加的内容的基础上，JSON格式的responseText 该页面正在接收。

I have a user script (for chrome and FF) that adds significant functionality to a page, but has recently been broken because the developers added some AJAX to the page. I would like to modify the script to listen to the pages xmlhttp requests, so that I can update my added content dynamically, based on the JSON formatted responseText that the page is receiving.

一个搜索已经打开了这应该工作，并在控制台上运行时做的工作很多功能。但是他们什么都不做，从用户脚本的情况下。

A search has turned up many functions that SHOULD work, and do work when run in the console. However they do nothing from the context of a user script.

(function(open) {

    XMLHttpRequest.prototype.open = function(method, url, async, user, pass) {

        this.addEventListener("readystatechange", function() {
            console.log(this.readyState);
        }, false);

        open.call(this, method, url, async, user, pass);
    };

})(XMLHttpRequest.prototype.open);

从：<一href="http://stackoverflow.com/questions/629671/how-can-i-intercept-xmlhtt$p$pquests-from-a-greasemonkey-script?answertab=active#tab-top">How我可以拦截XMLHtt prequests从的Greasemonkey脚本？

这完全在控制台中，我可以改变 this.readyState 到 this.responseText 和它的伟大工程（虽然在剧本我需要它来打开JSON数据转换成一个对象，然后让我userscript内操纵它。不只是写控制台）。但是如果我把它粘贴到一个userscript没有任何反应。似乎在页面上的xmlhttp请求不通过在userscript事件处理程序来检测。

This works perfectly in the console, I can change this.readyState to this.responseText and it works great (though in the script I will need it to turn the JSON data into an object, and then let me manipulate it within the userscript. Not just write to the console). However if I paste it into a userscript nothing happens. The xmlhttp requests on the page do not seem to be detected by the event handler in the userscript.

页面做的是使用jQuery $。获得（）函数的请求，如果能有什么关系呢。虽然我不认为它。

The page doing the requesting is using the jquery $.get() function, if that could have anything to do with it. Though I don't think it does.

我无法想象，没有办法，似乎是一个AJAX页面上运行的任何userscript希望这个能力。

I can't imagine that there isn't a way, seems like any userscript running on an AJAX page would want this ability.

推荐答案

由于该页面使用 $。获得（），它更容易拦截请求。使用 的ajaxSuccess（） 。

Since the page uses $.get(), it's even easier to intercept requests. Use ajaxSuccess().

这将工作在一个Greasemonkey的（火狐）脚本：
片段1：

This will work in a Greasemonkey(Firefox) script:
Snippet 1:

unsafeWindow.$('body').ajaxSuccess (
    function (event, requestData)
    {
        console.log (requestData.responseText);
    }
);

假设页面以正常方式（ $ 定义等）使用jQuery的。

Assuming the page uses jQuery in the normal way ($ is defined, etc.).

这应该在Chrome浏览器userscript工作（以及Greasemonkey的）：
片段2：

This should work in a Chrome userscript (as well as Greasemonkey):
Snippet 2:

function interceptAjax () {
    $('body').ajaxSuccess (
        function (event, requestData)
        {
            console.log (requestData.responseText);
        }
    );
}

function addJS_Node (text, s_URL, funcToRun) {
    var D                                   = document;
    var scriptNode                          = D.createElement ('script');
    scriptNode.type                         = "text/javascript";
    if (text)       scriptNode.textContent  = text;
    if (s_URL)      scriptNode.src          = s_URL;
    if (funcToRun)  scriptNode.textContent  = '(' + funcToRun.toString() + ')()';

    var targ    = D.getElementsByTagName('head')[0] || D.body || D.documentElement;
    targ.appendChild (scriptNode);
}

addJS_Node (null, null, interceptAjax);

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回复：

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Re:

怎么会那么做，我得到了数据的脚本？......（这样我就可以）以后使用该脚本中的数据。

"But how then do I get that data to the script? ... (So I can) use the data later in the script."

这工作在Greasemonkey的（火狐）;它也可能在工作Chrome的<一个href="https://chrome.google.com/webstore/detail/dhdgffkkebhmkfjojejmpbldmpobfkfo">Tampermonkey:
片段3：

This works in Greasemonkey(Firefox); it might also work in Chrome's Tampermonkey:
Snippet 3:

function myAjaxHandler (requestData) {
    console.log ('myAjaxHandler: ', requestData.responseText);
}

unsafeWindow.$('body').ajaxSuccess (
    function (event, requestData) {
        myAjaxHandler (requestData);
    }
);

但是，如果它没有，然后你不能共享一个浏览器userscript和目标页面之间的JS信息（容易） - 设计

But, if it doesn't then you cannot share JS information (easily) between a Chrome userscript and the target page -- by design.

通常情况下，你做的是注入整个userscript，让一切在页面范围内运行。像这样：
摘录4：

Typically what you do is inject your entire userscript, so that everything runs in the page scope. Like so:
Snippet 4:

function scriptWrapper () {

    //--- Intercept Ajax
    $('body').ajaxSuccess (
        function (event, requestData) {
            doStuffWithAjax (requestData);
        }
    );

    function doStuffWithAjax (requestData) {
        console.log ('doStuffWithAjax: ', requestData.responseText);
    }

    //--- DO YOUR OTHER STUFF HERE.
    console.log ('Doing stuff outside Ajax.');
}

function addJS_Node (text, s_URL, funcToRun) {
    var D                                   = document;
    var scriptNode                          = D.createElement ('script');
    scriptNode.type                         = "text/javascript";
    if (text)       scriptNode.textContent  = text;
    if (s_URL)      scriptNode.src          = s_URL;
    if (funcToRun)  scriptNode.textContent  = '(' + funcToRun.toString() + ')()';

    var targ    = D.getElementsByTagName('head')[0] || D.body || D.documentElement;
    targ.appendChild (scriptNode);
}

addJS_Node (null, null, scriptWrapper);

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