共享对象和包含而不安装在C ++在linux下 [英] Shared objects and inclusion without installation in C++ under linux

问题描述

我在写一个程序，它有两个库，我需要使用：v8和v8-juice。不幸的是，v8-juice不能编译成一个静态库，由于一些东西，它与模板。还有一些其他的奇怪，它需要v8编译为一个共享对象。

I'm writing a program that has two libraries that I need to use: v8, and v8-juice. Unfortunately, v8-juice can't be compiled as a static library due to some stuff it does with templates. There's some other quirks with it that require v8 to be compiled as a shared object as well.

所以，当我编译我的程序，我最终有两个共享对象是可执行文件运行所需要的。我的问题是，有没有一种方式，我可以包括这些共享对象而不安装在linux下？

So, when I compile my program, I end up having two shared objects that are needed for the executable to run. My question is, is there a way I can include these shared objects without installing them under linux? Sorry if it's a newbish question, I'm fairly new to C++.

推荐答案

共享库可以在同一个文件夹中，作为一个新的可执行文件。 man ld.so：

Shared libraries can be in the same folder as your executable. man ld.so:

   $ORIGIN and rpath

   ld.so  understands the string $ORIGIN (or equivalently ${ORIGIN}) in an
   rpath specification (DT_RPATH or DT_RUNPATH) to mean the directory con-
   taining  the  application  executable.  Thus, an application located in
   somedir/app could be compiled with gcc  -Wl,-rpath,'$ORIGIN/../lib'  so
   that  it  finds  an  associated shared library in somedir/lib no matter
   where somedir is located in the directory hierarchy.  This  facilitates
   the  creation  of  "turn-key"  applications  that  do  not  need  to be
   installed into special directories, but can instead  be  unpacked  into
   any directory and still find their own shared libraries.

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