c ++从stdin存储中读取向量和stdout [英] c++ read from stdin store in vector and stdout

问题描述

我测试这个代码，它读取stdin并将其存储在向量和stdout.any任何想法可能是什么问题

  #include< iostream> 
 #include< vector> 
 #include< string> 
 
 
使用namespace std; 
 
 int main（）{
 vector< string> vs; 
 vector< string> :: iterator vsi; 
 
字符串缓冲区; 
 while（！（cin.eof（）））{
 getline（cin，buffer）; 
 cout<<缓冲液< endl; 
 vs.push_back（buffer）; 
}; 
 
 for（int count = 1，vsi = vs.begin（）; vsi！= vs.end（）; vsi ++，count ++）{
 cout< string< count<<=< * vsi< endl; 
} 
 
 return 0; 
} 
 
 
 
 [root @ server dev]＃g ++ -o newcode newcode.cpp 
 newcode.cpp：在函数'int main（） '：
 newcode.cpp：19：error：can not convert'__gnu_cxx :: __ normal_iterator< std :: basic_string< char，std :: char_traits< char> ;, std :: allocator< char> > *，std :: vector< std :: basic_string< char，std :: char_traits< char>，std :: allocator< char> >，std :: allocator< std :: basic_string< char，std :: char_traits< char>，std :: allocator< char> > > > >'to'int'in initialization 
 newcode.cpp：19：error：没有匹配'operator！='in'vsi！= vs.std :: vector< _Tp，_Alloc> _Tp = std :: basic_string< char，std :: char_traits< char>，std :: allocator< char> >，_Alloc = std :: allocator< std :: basic_string< char，std :: char_traits< char>，std :: allocator< char> > >]（）'
 newcode.cpp：20：error：'unary *'的无效类型参数
 [root @ server dev]＃
  pre> 
 
解决方案
在 for 循环的初始化部分，  int 的新变量 vsi 。
 
 
 
解决问题的一种方法：
  vsi = vs.begin（）; 
 for（int count = 1; vsi！=vsend（）; ... 
  
 
i am testing out this code which reads stdin and stores it in vector and stdout..any idea what the problem could be??
#include <iostream>
#include <vector>
#include <string>


using namespace std;

int main() {
  vector<string> vs;
  vector<string>::iterator vsi;

  string buffer;
  while (!(cin.eof())) {
    getline(cin, buffer);
    cout << buffer << endl;
    vs.push_back(buffer);
  };

  for (int count=1 , vsi = vs.begin(); vsi != vs.end(); vsi++,count++){
    cout << "string" << count <<"="<< *vsi << endl;
  }

  return 0;
}



[root@server dev]# g++ -o newcode newcode.cpp 
newcode.cpp: In function ‘int main()’:
newcode.cpp:19: error: cannot convert ‘__gnu_cxx::__normal_iterator<std::basic_string<char, std::char_traits<char>, std::allocator<char> >*, std::vector<std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::allocator<std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > >’ to ‘int’ in initialization
newcode.cpp:19: error: no match for ‘operator!=’ in ‘vsi != vs.std::vector<_Tp, _Alloc>::end [with _Tp = std::basic_string<char, std::char_traits<char>, std::allocator<char> >, _Alloc = std::allocator<std::basic_string<char, std::char_traits<char>, std::allocator<char> > >]()’
newcode.cpp:20: error: invalid type argument of ‘unary *’
[root@server dev]# 

解决方案
In the initialization part of the for loop, you declare a new variable vsi whose type is int.

One way to fix the problem:
vsi = vs.begin();
for (int count=1; vsi != vs.end(); ...


                        
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