在类构造函数中实例化供应商类 [英] Instantiating a vendor class in class constructor

问题描述

在我的CakePHP 2应用程序中，我有这样的供应商。我需要在我的控制器类中创建一个这个供应商类的实例。所以我将在控制器的不同函数中使用该实例。

In my CakePHP 2 application I have such vendor. I need to create an instance of this vendor class inside my controller class. So I will use that instance inside my controller's different functions.

App::import('Vendor', 'fancyVendor', array('file' => 'fancyVendor.php'));

class MyController extends AppController {

    public $fancyVendor;

    function beforeFilter() {
       $fancyVendor = new fancyVendor();
       $fancyVendor->setValue("12");
    }

    function showMe() {
       echo $fancyVendor->getValue();
    }
}

在我的 showMe ，我不能得到我在 beforeFilter 函数中设置的值。是否有正确的实例化方法？

Inside my showMe function, I can't get the value that I set inside my beforeFilter function. Is there a proper way to instantiate it?

推荐答案

您需要了解 scope 。您已在 beforeFilter（）作用域中初始化了一个变量，然后尝试在 showMe 作用域中使用它。两个是完全不同的。

You need to learn about scope. You have initialised a variable in the beforeFilter() scope and then trying to use it in the showMe scope. The two are completely different.

您可以创建一个范围限定为整个类的变量，通常称为属性...

You can make a variable that is scoped to the entire class, normally called a property...

function beforeFilter() {
   $this->fancyVendor = new fancyVendor();
   $this->fancyVendor->setValue("12");
}

function showMe() {
   echo $this->fancyVendor->getValue();
}

另一点要注意的是，您可以使用 App :: uses（）方法来加载类。根据你的命名它会工作。 （类是以这种方式加载的）

Another point to note is that you can use the App::uses() method to load the class. According to your naming it would work. (class is lazy loaded this way)

App::uses('fancyVendor', 'Vendor');

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