在控制器中访问另一个CakePHP的模型的最佳方法是什么？ [英] What is the best way to access another CakePHP's Model in a Controller?

问题描述

说我有两个控制器，如 Table1sController 和 Table2sController 。
对应的模型： Table1sModel ， Table2sModel 。

Say I got two Controllers like this Table1sController, and Table2sController. With corresponding models: Table1sModel, Table2sModel.

在 Table1sController 中，我有：

$this->Table1sModel->action();

说我想要访问 Table2sModel 。

如何在 Table1sController 中执行类似的操作？
我在Table1sController中尝试过：

How is it possible to do something like this in Table1sController? I have tried this in Table1sController:

$this->Table2sModel->action();

但我收到如下的错误信息：

But I received an error message like this:

未定义的属性：Table1sController :: $ Table2sModel

Undefined property: Table1sController::$Table2sModel

推荐答案

如果您的模型已定义关联（hasMany等），那么您可以访问该模型的方法在Model1Controller中）与：

If your models have defined associations (hasMany, etc.), then you can access that model's methods (assuming you're in Model1Controller) with:

$this->Model1->Model2->method();

如果两个模型之间没有模型关联，但您想要使用Model2方法，可以在modelessage的$ uses属性中添加一个条目。请参见 http://book.cakephp.org/2.0/ en / controllers.html＃components-helpers-and-uses

If there is no model association between the two models, but you want to be able to use the Model2's methods, you can add an entry in the $uses attribute of model1Controller. See http://book.cakephp.org/2.0/en/controllers.html#components-helpers-and-uses

最后，如果它是暂时连接（你不想加载其他模型，因为你只是很少去访问model2），请查看手册的关于创建/销毁关联的部分，在 http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html

Finally, if it's a transitory connection (you don't want the overhead of loading other models every time, because you're only rarely going to access model2), check out the manual's section on creating / destroying associations on the fly, at http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html

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