ACL - 在哪里配置自定义userModel的授权？ [英] ACL - Where to configure custom userModel for authorize?

问题描述

我有Auth的 Player 而不是默认的 User 模型。
我最近为我的应用程序配置ACL，并尝试通过返回false 在我的 isAuthorized（$ player）函数，发生以下错误：

I'm having Player instead of default User model for my Auth. I recently configured ACL for my app and while trying to do testing by return false in my isAuthorized($player) function, the following error occured:

AclNode::node() - Couldn't find Aro node identified by
Array ( [Aro0.model] => User [Aro0.foreign_key] => 1 )

Aro0.model 不是玩家吗？我找不到要更改 Auth-> authorize 的位置。 Auth-authenticate 工作正常，因为我管理登录，因为有一个 userModel 选项允许我指定一个自定义模型用户登录。

Isn't the Aro0.model suppose to be Player? I can't find where to change for Auth->authorize. Auth-authenticate works fine as I manage to login since there is a userModel option allow me to specify a custom Model for user login.

这是我的AppController

Here's My AppController

class AppController extends Controller
{
    public $components = array(
        'Session',
        'Acl',
        'RequestHandler',
        'Auth' => array(

            'authorize' => array(
                'controller',
                'Actions' => array('actionPath' => 'controllers'),
            ),

            'authenticate' => array(
                'Form' => array(
                    'userModel' => 'Player',
                    'fields' => array('username' => 'email', 'password' => 'password'),
                    )
                )
            ),
        );
    public $helpers = array('Html', 'Form', 'Session');

    function isAuthorized($player)
    {
        //var_dump($player); die;
        return false;
        return $this->Auth->loggedIn();
    }

}

推荐答案

解决。它是将 userModel 与 actionPath 一起附加。

Solved. it is to append userModel together with actionPath.

$this->Auth->authorize = array(
    AuthComponent::ALL => array('actionPath' => 'controllers/', 'userModel' => 'Player'),
    'Actions',
    'Controller'
);

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