一个形成两个动作 [英] One form two action

问题描述

您好，我有几个表单字段我想点击按钮的控制被发送到操作1，但
的点击按钮2它必须发送到操作2.目前我使用js以在点击时动态地改变表单动作。但是有什么其他解决方案。

Hi i have a few form fields i want the on click of button a the control to be sent to action 1 but on click of button 2 it has to be sent to action 2. Currently i am using js to change the form action dynamically on click. but is there any other solution. I cant do the checking after submit in a same method thet have to be two different methods.

在这种情况下，2个按钮是视图（需要显示html数据）并下载（与csv文件相同的数据）。我使用cakephp 1.2，但我觉得这更像是一个通用的问题

The 2 buttons in this case are view(html data needs to be displayed) and download(same data as csv file). I am using cakephp 1.2 but i feel this is more of a generic problem

推荐答案

HTML5有 formaction 属性

<form action="/url" id="myForm">
     <input type="submit" value="save1" formAction="/url1" />
     <input type="submit" value="save2" formAction="/url2" />
</form>

如果需要，这里是备用。

Here is a fallback if you need it.

if (!('formAction' in document.createElement('input'))){
 $('form').on('click', 'input[type=submit]', function (e) {
    var attr = this.getAttribute('formAction');

    if (attr) {
        this.action = attr; //Set the form's action to formAction
    }
  });
}

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