Cake PHP - 如何访问由Pagination发现的特殊模型? [英] Cake PHP - How to access a special Model found by Pagination?
问题描述
我有以下代码来获得与另一个与实际对象相关的模型相关的特殊模型:(我想要的模型 - 在Rubric模型视图中)
$ this-> paginate = array(
'Entrieslocation'=> array(
'conditions'=> array('Entrieslocation.rubric_id' => $ this-> Rubric-> id,'Entrieslocation.subrubric_id'=>'0'),
'joins'=& alias'=>''Entry',
'table'=>'entries',
'type'=>'INNER',
'conditions'=> id = Entrieslocation.entry_id'
)
)
)
);
然后我想我可以这样得到:
$ this-> set('entries',$ this-> paginate('Entry'));
但是变量为空,我如何访问视图中的Pagination中的Entries? p>
上面的代码生成的查询是正确的,我通过输入查询到phpmyadmin查看。
感谢您的帮助:)
首先,你必须在控制器类下面定义$ paginate变量。例如
class UsersController extends AppController {
public $ paginate = array
}
然后在您的操作中按照以下方式获取分页结果。
$ this-> paginate = array(
'recursive'=> -1,
'limit'=> 10,
'conditions'=> array('Your conditions'),
'fields'=> array('Entry。*,Entrieslocations。*'
'joins'=& array(
array(
'table'=>'Entrieslocations',
'alias'=>'Entrieslocation',
'type'=>'inner',
'conditions'=>'Entry.id = Entrieslocation.entry_id'
),
),
'order'=> ; array(
'Entry.id'=>'desc'
)
);
$ entries = $ this-> paginate('Entry');
要将结果集传递到视图,请使用以下命令:
$ this-> set('entries',$ entries);
I have the following Code to get a special model related to another model related to actual object: (I want the Entry-model - in the Rubric-model-view)
$this->paginate = array(
'Entrieslocation' => array(
'conditions' => array('Entrieslocation.rubric_id' => $this->Rubric->id, 'Entrieslocation.subrubric_id' => '0'),
'joins' => array(
array(
'alias' => 'Entry',
'table' => 'entries',
'type' => 'INNER',
'conditions' => 'Entry.id = Entrieslocation.entry_id'
)
)
)
);
Then I thought I could get it by something like this:
$this->set('entries', $this->paginate('Entry'));
But the variable is empty, how can I access the Entries inside the Pagination in the view?
The Query generated by the code above is correct, I checked it by entering the query into phpmyadmin. So how can I access the result (only the Entries)?
Thanks for your help :)
First of all you must define $paginate variable below controller class. For example
class UsersController extends AppController {
public $paginate = array();
}
Then in your action follow following patter to get the paginated result.
$this->paginate = array(
'recursive' => -1,
'limit' => 10,
'conditions' => array('Your conditions'),
'fields' => array('Entry.*, Entrieslocations.*'),
'joins' => array(
array(
'table' => 'Entrieslocations',
'alias' => 'Entrieslocation',
'type' => 'inner',
'conditions' => 'Entry.id = Entrieslocation.entry_id'
),
),
'order' => array(
'Entry.id' => 'desc'
)
);
$entries = $this->paginate('Entry');
To pass result set to the view use following:
$this->set('entries', $entries);
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