是否有可能捕获在异步回调中抛出的异常？ [英] Is it possible to catch exceptions thrown in a JavaScript async callback?

问题描述

有没有办法在JavaScript回调中捕获异常？是否可能？

Is there a way to catch exceptions in JavaScript callbacks? Is it even possible?

Uncaught Error: Invalid value for property <address>

这里是jsfiddle： http://jsfiddle.net/kjy112/yQhhy/

Here is the jsfiddle: http://jsfiddle.net/kjy112/yQhhy/

try {
    // this will cause an exception ing google.maps.Geocoder().geocode() 
    // since it expects a string.
    var zipcode = 30045; 
    var map = new google.maps.Map(document.getElementById('map_canvas'), {
        zoom: 5,
        center: new google.maps.LatLng(35.137879, -82.836914),
        mapTypeId: google.maps.MapTypeId.ROADMAP
    });
    // exception in callback:
    var geo = new google.maps.Geocoder().geocode({ 'address': zipcode }, 
       function(geoResult, geoStatus) {
          if (geoStatus != google.maps.GeocoderStatus.OK) console.log(geoStatus);
       }
    );
} catch (e) {
    if(e instanceof TypeError)
       alert('TypeError');
    else
       alert(e);
}​

推荐答案

t catch你的例子中的任何东西是因为一旦 geocode（）回调被调用， try / catch 。因此， geocode（）回调在 try 块的范围之外执行，因此无法捕获。

The reason it won't catch anything in your example is because once the geocode() callback is called, the try/catch block is over. Therefore the geocode() callback is executed outside the scope of the try block and thus not catchable by it.

据我所知，不可能捕获在JavaScript回调中抛出的异常（至少不是以任何直接的方式）。

As far as I know, it is not possible to catch exceptions thrown in JavaScript callbacks (at least, not in any straightforward manner).

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