如何检查对象以查看其类型并返回Casted对象 [英] How Can I Check an Object to See its Type and Return A Casted Object
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问题描述
我有一个方法,我通过一个对象。在这种方法,我检查它的类型,并根据类型我做的东西,并返回一个长。我试过了每一种方式,我可以想到这样做,我总是得到几个编译器错误告诉我它期望一个特定的对象,但另一个。有人可以向我解释我做错了,指导我在正确的方向?我到目前为止的尝试如下:
I have method to which I pass an object. In this method I check it's type and depending on the type I do something with it and return a Long. I have tried every which way I can think of to do this and I always get several compiler errors telling me it expects a certain object but gets another. Can someone please explain to me what I am doing wrong and guide me in the right direction? What I have tried thus far is below:
override def getInteger(obj:Object) = {
if (obj.isInstanceOf[Object]) null
else if (obj.isInstanceOf[Number])
(obj:Number).longValue()
else if (obj.isInstanceOf[Boolean])
if (obj:Boolean) 1 else 0
else if (obj.isInstanceOf[String])
if ((obj:String).length == 0 | (obj:String) == "null")
null
else
try {
Long.parse(obj:String)
} catch {
case e: Exception => throw new ValueConverterException("value \"" + obj.toString() + "\" of type " + obj.getClass().getName() + " is not convertible to Long")
}
}
推荐答案
模式匹配会让它更好。
Pattern matching would make it much more nicer.
def getInteger(obj: Any) = obj match {
case n: Number => n.longValue
case b: Boolean => if(b) 1 else 0
case s: String if s.length != 0 && s != "null" => s.toLong
case _ => null
}
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