是Guid是原始类型还是复杂类型？ [英] Is a Guid a primitive type or a complex type?

问题描述

我们通过原始类型和我们要扩展的复杂类型来分离扩展方法类。我的问题很简单。将Guid与字符串，int，DateTime等一起被认为是原始类型？

We separate out extension method classes by primitive types and complex types that we are extending. My question is simple. Would a Guid be considered a primitive type along with string, int, DateTime, etc? Or would it be considered a complex type when describing it?

在回顾我的答案后，我非常欣赏澄清，我能够从一些答案收集。

After reviewing the answers I much appreciate the clarification that I was able to glean from some answers. However, I am getting the impression that curiosity killed the cat got the cat murdered, so I am voting to close my own question.

推荐答案

这取决于你所谓的原始数据类型。

It depends on what you call a "primitive data type".

维基百科列出了这两个定义：

• 基本类型是数据类型由作为基本构建块的编程语言提供。大多数语言允许从基本类型开始递归构造更复杂的复合类型。


• 内置类型是编程语言提供内置支持的数据类型。

根据第一个， Guid 是一个构造类型， / strong>一个原始类型。

According to the first one, Guid is a constructed type, not a primitive.

根据第二个，它也是不一个原始类型（因为它在BCL中提供， System 命名空间，并且未由任何.NET语言定义）。

According to the second, it is also not a primitive type (as it is provided in the BCL, in the System namespace, and is not defined by any of the .NET languages).

更新：

这是类型类的type.isprimitive.aspxrel =nofollow> IsPrimitive 方法说：

This is what the IsPrimitive method of the Type class says:

基本类型是布尔值，字节，SByte，Int16，UInt16，Int32，UInt32，Int64，UInt64，IntPtr，UIntPtr，Char， Double和Single。

The primitive types are Boolean, Byte, SByte, Int16, UInt16, Int32, UInt32, Int64, UInt64, IntPtr, UIntPtr, Char, Double, and Single.

因此，就.NET而言，不类型。

So, as far as .NET is concerned, it is not a primitive type.

结论：根据上述三个独立标准， Guid 是绝对不原始类型。

In conclusion: According to the three separate criteria above, Guid is definitely not a primitive type.

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