如何检查字符串是否有4个连续的字符后没有元音 [英] How to check if string has no vowel after 4 consecutive chars

问题描述

我想检查用户是否输入了接近有效名称的内容。所以如果它输入像 gbcvcvrt ，我想验证它，并将其标记为不是一个真实的名称。类似 theg + vowel 应该被验证为正确的名称。

I want to check if a user is entering something close to a valid name. So if it's entered something like gbcvcvrt, I would want to validate it and mark this as not a real name. Something like theg+vowel should be validated as the right name.

在任何长度的字符串，代码应该检测四个连续的非元音字母。
我不希望任何人的名字是节奏的方式

On any length of string the code should detect four consecutive non vowel alphabets. I don't expect anyone's name to be rhythm by the way

考虑

$String = 'therhythm';

我们不能检查前四个字符，我们必须遍历整个字符串并检查四个任何四个连续的非元音字母，而不管它们位于什么字符串上。这样我们可以验证$ String为无效，即使前五个字符将验证它，如果我们检查前四个字母。

We can't check for the first four chars, we have to go through the entire string and check four any four consecutive non-vowel alphabets regardless of where on the string they are situated. That way we can validate $String as not valid even though the first five chars would validate it if we were checking the first four alphabets.

• 不应包含3个连续的元音，


• 不应包含数字，


• 非字母字符

推荐答案

edit：您可以为此使用以下正则表达式：

Based on your latest edit: You can use following regex for this:

^(?!.*?[^aeiou]{5})(?!.*?[aeiou]{3})[a-z]*$

在线演示： http://regex101.com/r/vM0aN9

分拆：

Online Demo: http://regex101.com/r/vM0aN9

Breaking it down:

• [^ aeiou] = >匹配任何东西，除了元音之外


• （？！*。[^ aeiou] {5}） =>没有5个连续辅音的情况


• （？！。*？[aeiou] {3}） =>没有连续3个元音的情况


• [az] * =>确保输入中只有字母
• 
  

• [^aeiou] => Match anything but vowels
• (?!.*?[^aeiou]{5}) => Negative lookahead to make sure there is no case of 5 consecutive consonants
• (?!.*?[aeiou]{3}) => To make sure there is no case of 3 consecutive vowels
• [a-z]* => To make sure there are only letters in the input

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