选择随机字符 [英] Pick random char

问题描述

我有一些字符：

chars = "$%#@!*abcdefghijklmnopqrstuvwxyz1234567890?;:ABCDEFGHIJKLMNOPQRSTUVWXYZ^&".ToCharArray();

现在我正在寻找一个从这些返回一个随机字符的方法。

now i'm looking for a method to return a random char from these.

我发现一个代码可能是有用的：

I found a code which maybe can be usefull:

static Random random = new Random();
        public static char GetLetter()
        {
            // This method returns a random lowercase letter
            // ... Between 'a' and 'z' inclusize.
            int num = random.Next(0, 26); // Zero to 25
            char let = (char)('a' + num);
            return let;
        }

此代码返回一个字母表中的随机字符，但只返回小写字母

this code returns me a random char form the alphabet but only returns me lower case letters

推荐答案

好了，你几乎要从字符串返回一个随机元素，所以你只是生成一个随机number在字符串长度范围内：

Well you're nearly there - you want to return a random element from a string, so you just generate a random number in the range of the length of the string:

public static char GetRandomCharacter(string text, Random rng)
{
    int index = rng.Next(text.Length);
    return text[index];
}

我建议 使用 static 类型的变量随机没有任何锁定，顺便 - 随机不是线程安全的。有关详情（和解决方法），请参阅我的随机数字。

I'd advise against using a static variable of type Random without any locking, by the way - Random isn't thread-safe. See my article on random numbers for more details (and workarounds).

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