在Java中迭代字符串的字符的最简单/最好/最正确的方法是什么？ [英] What is the easiest/best/most correct way to iterate through the characters of a string in Java?

问题描述

StringTokenizer ？将 String 转换为 char [] 并迭代？我使用一个for循环来迭代字符串并使用 charAt（）

code>来获取每个字符来检查它。由于String是用数组实现的，所以 charAt（）方法是一个常量时间操作。

  String s =... stuff ...; 
 
 for（int i = 0; i  char c = s.charAt（i）; 
 //进程char 
} 
  

对我来说似乎是最容易的。

至于正确性，我不相信这里存在。这都是基于你的个人风格。

StringTokenizer? Convert the String to a char[] and iterate over that? Something else?

解决方案

I use a for loop to iterate the string and use charAt() to get each character to examine it. Since the String is implemented with an array, the charAt() method is a constant time operation.

String s = "...stuff...";

for (int i = 0; i < s.length(); i++){
    char c = s.charAt(i);        
    //Process char
}

That's what I would do. It seems the easiest to me.

As far as correctness goes, I don't believe that exists here. It is all based on your personal style.

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