字符更改时拆分字符串。可能的Regex解决方案？ [英] Split String when character changes. Possible Regex solution?

问题描述

我有一些 String 只由数字组成，我想在字符变化时拆分。

I have some Strings consisting of only digits, and I want to split it whenever the character changes.

例如：

• 11101100112021120转到： {111，11，11，2，2，11，2}


• code>222222222转到 {222222222}


• 222222122转到 {222222，1，22}


• 000000000转到 {}


• 0000100000转到 {1}


• 11121222212112133321 到 {111，2，1，2222，1，2，11，2 1，333，2，1}

• "11101100112021120" goes to: {"111", "11", "11", "2", "2", "11", "2"}
• "222222222" goes to {"222222222"}
• "222222122" goes to {"222222", "1", "22"}
• "000000000" goes to {}
• "0000100000" goes to {"1"}
• "11121222212112133321" goes to {"111", "2", "1", "2222", "1", "2", "11", "2", "1", "333", "2", "1"}

这样做。

我知道两种方法：只是暴力强制，或者逐节添加。或者，我可以通过删除所有的0，并替换为0，然后添加0，当字符更改，然后只是做一个拆分0，但这两种方式只是看起来愚蠢。

I know two ways to go about this: just brute forcing, or adding section by section. Or, I could go through and remove all 0's and replace with a 0, then add 0's when characters change, and then just do a split on 0's, but both of those ways just look dumb. If anyone has any idea on a better/prettier way to do this, regex or logic, it'd be nice.

推荐答案

如果有任何人有更好/更好的方式来做这个，regex或逻辑，

This seems to work like you expect

data.split("0+|(?<=([1-9]))(?=[1-9])(?!\\1)");

测试：

String[] tests = { "11101100112021120", "222222222", "222222122",
        "000000000", "0000100000", "11121222212112133321" };

for (String data : tests) {
    System.out.println(data + " ->" + Arrays.toString(data.split("0+|(?<=([1-9]))(?=[1-9])(?!\\1)")));
    System.out.println("-----------------------");
}

输出：

11101100112021120 ->[111, 11, 11, 2, 2, 11, 2]
-----------------------
222222222 ->[222222222]
-----------------------
222222122 ->[222222, 1, 22]
-----------------------
000000000 ->[]
-----------------------
0000100000 ->[, 1]     // <-- only problem - empty first element 
-----------------------
11121222212112133321 ->[111, 2, 1, 2222, 1, 2, 11, 2, 1, 333, 2, 1]
-----------------------

不幸的是，前导零会让数组包含额外的空字符串。要摆脱它，你可以更早删除这些零与 data.replaceFirst（^ 0 +（？= [^ 0]），）

Unfortunately leading zeros will let array to contain additional empty String. To get rid of it you can earlier remove these zeros with data.replaceFirst("^0+(?=[^0])", "")

这篇关于字符更改时拆分字符串。可能的Regex解决方案？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！