如何删除字符串中某个字符后的所有内容？ [英] How to delete everything after a certain character in a string?

问题描述

如何删除python中字符串的某个字符后的所有内容？例如，我有一个包含文件路径和一些额外字符的字符串。我如何删除.zip之后的所有内容？我尝试过 rsplit 和 split ，但是在删除多余的字符时没有包括.zip。

How would I delete everything after a certain character of a string in python? For example I have a string containing a file path and some extra characters. How would I delete everything after .zip? I've tried rsplit and split , but neither included the .zip when deleting extra characters.

任何建议？

推荐答案

只需取第一部分， code>'。zip'返回：

Just take the first portion of the split, and add '.zip' back:

s = 'test.zip.zyz'
s = s.split('.zip', 1)[0] + '.zip'

$ b b

或者你可以使用切片，这里是一个解决方案，你不需要添加'。zip'回到结果> 4 来自 len（'。zip'））：

Alternatively you could use slicing, here is a solution where you don't need to add '.zip' back to the result (the 4 comes from len('.zip')):

s = s[:s.index('.zip')+4]

或使用正则表达式的另一个选择：

Or another alternative with regular expressions:

import re
s = re.match(r'^.*?\.zip', s).group(0)

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