如何在Java输出中显示特殊的转义字符如LineBreak? [英] How to show special escape characters like LineBreak in Java output?
问题描述
找不到解决方案似乎是一个简单的问题。例如,我有一个字符串与LineBreaka \\\
a。此字符串的System.out.println输出显示2行。但是,我需要以完全相同的形式显示输出,即a \\\
a。如何实现这一目标?
Cannot find a solution to seem to be a simple question. For example, I have a string with LineBreak "a\na". The System.out.println output of this string shows 2 lines. However, I need to show the output in exactly the same form, i.e. "a\na". How to achieve this?
推荐答案
您需要转义 \\\
添加一个反斜杠。
You need to escape your \n
with an extra backslash..
使用: - a\\\\
c $ c> \ n 。
a
Use: - "a\\na"
to get \n
in your output..
System.out.println("a\\na"); // Prints a\na
或者,您也可以查看: - Apache Commons
StringEscapeUtils#escapeJava
将自动排除所有具有额外反斜杠的所有特殊
转义序列
。
Or, you can also take a look at :- Apache Commons
StringEscapeUtils#escapeJava
which will automatically excape all the special escape sequences
with an extra backslash..
String str = "a\nb\r\t";
String result = StringEscapeUtils.escapeJava(str); // Takes `\n` as `\\n`
System.out.println(result);
这将打印: - a\\\
b\r\t
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