如何将带有空终止字符的字节数组转换为Java中的字符串？ [英] How do I convert a byte array with null terminating character to a String in Java?

问题描述

如何从字节数组创建一个String对象

  byte arr [MAX_SIZE] // Java 
  

其中一个数组元素是C null终止字节？就像调用

一样简单

  String str = new String（arr）; 
  

String构造函数是否知道会在null终止字符处自动停止？空字节后的任何字节都是（可能）无用的字符，我不想包括在字符串中。 解析Java中的字节数组中的最后一个响应建议循环访问数组，并手动查找null终止字符，但我想知道String构造函数是否会自动执行。我还假设系统的默认字符集将在所有的端点使用。

解决方案

  [] = ... 
 Charset charset = ... 
 int i; 
 for（i = 0; i  String str = new String（arr，0，i，charSet） ; 
  

注意：

• 使用显式的CharSet参数通常是个好主意，因此您的应用程式不依赖于平台的预设字元/编码。



• p>这不适用于某些字符集。例如，UTF-16编码的字符串不能安全地表示为零终止的字节序列，因为许多代码单元包含零字节。 （另一方面，如果字符串不包含代码点零的实例，则UTF-8是正常的;参见 UTF-8是否包含零字节？）

...但我想知道String构造函数是否会自动执行此操作。

不，它们不会。 （不要奇迹...读取javadoc： - ））

我也假设系统的默认字符集所有结束。

如果不指定字符集，将使用Java平台的默认值。这可能是系统的默认值，但不能保证。

How can I create a String object from a byte array

byte arr[MAX_SIZE];  // Java

where one of the array elements is a C null terminating byte? Is it as simple as calling

String str = new String( arr );

Will the String constructor know to automatically stop at the null terminating character? Any bytes after the null byte are (possibly) garbage characters that I don't want to include in the string. The last response under Parsing byte array in java suggests looping through the array and manually finding the null terminating character, but I was wondering whether the String constructor will do this automatically. I also assume the system's default charset will be used on all ends.

解决方案

byte arr[] = ...
Charset charset = ...
int i;
for (i = 0; i < arr.length && arr[i] != 0; i++) { }
String str = new String(arr, 0, i, charSet);

Notes:

• It is generally a good idea to use an explicit CharSet parameter so that your application doesn't depend on the platform's default characterset / encoding.

• This won't work for some charsets. For instance, a UTF-16 encoded string can't safely be represented as a zero-terminated byte sequence because many code units contain zero bytes. (On the other hand, UTF-8 is OK provided that the string contains no instances of code point zero; see Can UTF-8 contain zero byte?)

... but I was wondering whether the String constructor will do this automatically.

No it / they won't. (Don't "wonder" ... read the javadoc :-))

I also assume the system's default charset will be used on all ends.

If you don't specify a charset, the Java platform's default will be used. This is likely to be the system default, but that is not guaranteed.

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