使用Java中的固定字母集编码/解码长字符串到字符串 [英] Encode/decode a long to a string using a fixed set of letters in Java

问题描述

给定任意字母集

String range = "0123456789abcdefghijklmnopABCD#";

我正在寻找2个方法来编码/解码从long < - > String

I am looking for 2 methods to encode/decode from long <-> String

String s = encode( range, l );

和

long l = decode( range, s );

因此 decode（range，encode（range，123456789L））== 123456789L

So decode(range, encode(range, 123456789L)) == 123456789L

如果范围是0123456789，这是通常的编码方式。

And if range is "0123456789" thats the usual way of encoding.

推荐答案

以下代码可以满足您的需要：

The following code does what you need:

static long decode(String s, String symbols) {
    final int B = symbols.length();
    long num = 0;
    for (char ch : s.toCharArray()) {
        num *= B;
        num += symbols.indexOf(ch);
    }
    return num;
}
static String encode(long num, String symbols) {
    final int B = symbols.length();
    StringBuilder sb = new StringBuilder();
    while (num != 0) {
        sb.append(symbols.charAt((int) (num % B)));
        num /= B;
    }
    return sb.reverse().toString();
}
public static void main(String[] args) {
    String range = "0123456789abcdefghijklmnopABCD#";
    System.out.println(decode(encode(123456789L, range), range));
    // prints "123456789"

    System.out.println(encode(255L, "0123456789ABCDEF"));
    // prints "FF"

    System.out.println(decode("100", "01234567"));
    // prints "64"
}

• 用不同字母表长度替换密码

• substitution cypher with different alphabet length

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