获取的Google+股没有API密钥的每一页？ [英] Get Google+ shares without API key for each page?

问题描述

在搜索结果页，我想获得的Google+股份数为每个搜索结果项的通过Ajax的URL。我已经成功地设置了计数功能的Facebook和Twitter的：

On a search result page I would like to get the count of Google+ shares for the URL of each search result item via Ajax. I already managed to set up counting functions for Facebook and Twitter:

    $.getJSON('http://urls.api.twitter.com/1/urls/count.json?url=' + url + '&callback=?', function(data){
        tweets = data.count;
    });

    $.getJSON('https://api.facebook.com/method/links.getStats?urls='+ url+'&format=json', function(data){
        fblikes = data[url].shares;
    });

有关Google+的我也已经找到了解决办法，但这需要的API密钥对每个URL。有没有什么办法来检索的Google+计数，而这样的关键？使用它吨动态加载搜索结果，当然我不能创建一个API密钥为每个搜索结果的网址。

For Google+ I also already found a solution, but this requires the API Key for each URL. Is there any way to retrieve the Google+ count without such a key? Using it for tons of dynamically loaded search results, of course I cannot create an API key for each search result URL.

推荐答案

是的，有可能获得谷歌+1计数。他们通过JSON-RPC POST调用检索。

Yes, it's possible to get Google +1 counts. They are retrieved via a JSON-RPC POST call.

POST网址：

https://clients6.google.com/rpc?key=AIzaSyCKSbrvQasunBoV16zDH9R33D88CeLr9gQ 

帖子正文：

<$c$c>[{"method":"pos.plusones.get","id":"p","params":{"nolog":true,"id":"%%URL%%","source":"widget","userId":"@viewer","groupId":"@self"},"jsonrpc":"2.0","key":"p","apiVersion":"v1"}]

其中， %% URL %% 是所需的URL。

where %%URL%% is the desired URL.

看一看下面的：

• <一个href="http://stackoverflow.com/questions/21524077/getting-google-1-page-shares-via-ajax-hidden-api/21866500#21866500">Getting通过AJAX（隐藏API）
谷歌+1页股
• http://www.sharedcount.com/documentation.php

• Getting google +1 Page shares via AJAX (hidden Api)
• http://www.sharedcount.com/documentation.php

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