Python：绑定未绑定的方法？ [英] Python: Bind an Unbound Method?

问题描述

在Python中，有没有办法绑定一个未绑定的方法而不调用它？

In Python, is there a way to bind an unbound method without calling it?

我编写一个wxPython程序， d很好将所有我的按钮的数据组合为一个类级别的元组列表，例如：

I am writing a wxPython program, and for a certain class I decided it'd be nice to group the data of all of my buttons together as a class-level list of tuples, like so:

class MyWidget(wx.Window):
    buttons = [("OK", OnOK),
               ("Cancel", OnCancel)]

    # ...

    def Setup(self):
        for text, handler in MyWidget.buttons:

            # This following line is the problem line.
            b = wx.Button(parent, label=text).Bind(wx.EVT_BUTTON, handler)

问题是，因为 handler 的所有值都是未绑定的方法，我的程序在一个壮观的火焰中爆炸，我哭了。

The problem is, since all of the values of handler are unbound methods, my program explodes in a spectacular blaze and I weep.

我在网上寻找一个解决方案，似乎应该是一个相对直接，可解决的问题。不幸的是我找不到任何东西。现在，我使用 functools.partial 来解决这个问题，但是有没有人知道是否有一个干净，健康，Pythonic的方式绑定一个未绑定的方法

I was looking around online for a solution to what seems like should be a relatively straightforward, solvable problem. Unfortunately I couldn't find anything. Right now, I'm using functools.partial to work around this, but does anyone know if there's a clean-feeling, healthy, Pythonic way to bind an unbound method to an instance and continue passing it around without calling it?

推荐答案

所有函数也都是描述符可以通过调用 __ get __ 方法绑定它们：

All functions are also descriptors, so you can bind them by calling their __get__ method:

bound_handler = handler.__get__(self, MyWidget)

这里是R. Hettinger的优秀指南到描述符。

Here's R. Hettinger's excellent guide to descriptors.

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