PHP类实例化。要使用还是不使用括号？ [英] PHP class instantiation. To use or not to use the parentheses?

问题描述

我一直假设 - 在没有构造函数参数的情况下，在创建类实例时，括号（大括号）跟随类名称，是可选的，并且您可以根据自己的个人喜好包含或排除它们。

I've always assumed that - in the absence of constructor parameters - the parentheses (curly brackets) follow the class name when creating a class instance, were optional, and that you could include or exclude them at your own personal whim.

这两个语句是相等的：

$foo = new bar;
$foo = new bar();

我是对吗？

我知道这听起来像一个RTFM问题，但我一直在寻找一段时间（包括整个PHP OOP部分），我似乎找不到一个直接的答案。

I know this sounds like a RTFM question, but I've been searching for a while (including the entire PHP OOP section) and I can't seem to find a straight answer.

推荐答案

如果您不是通过任何代码约定编写代码，请使用您更喜欢的代码。就我个人而言，我喜欢离开它，因为它真的只是杂乱的给我。

They are equivalent. If you are not coding by any code convention, use which you like better. Personally, I like to leave it out, as it is really just clutter to me.

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