为什么在类中实现的C＃接口方法必须是public的？ [英] Why must an C# interface method implemented in a class be public?

问题描述

我有一个类继承一个接口。接口成员方法在我的类中实现，没有访问修饰符（因此，默认情况下它是私有的）。

I have a class which inherits an interface. An interface member method is implemented in my class without an access modifier (so, by default it's private ) .

我收到错误无法实现一个接口成员，因为它不是公共的。

I am getting the error "cannot implement an interface member because it is not public".

为什么不允许？

推荐答案

这里是为什么感觉能够覆盖可见性：

Here's an example of why it doesn't make sense to be able to override the visibility:

interface someI
{
    void doYourWork();
}
public class A : someI
{
    public void doYourWork()
    {
        //...
    }
}

public class B : someI
{
    private void doYourWork()
    {
        //...
    }
}
void Main()
{
    List<someI> workers = getWorkers();
    foreach(var worker in workers)
        worker.doYourWork();
}

当你的工人是B类型时会发生什么？你正在调用一个方法，就像它是public的，但它是一个私有方法。如果你想要这个功能，那么它不是一个真正的私有方法吗？

What happens when your worker is of type B? You're calling a method as if it were public, but it's a private method. If you want this functionality, then it's not really a private method is it?

如果你只想通过你的接口引用它，你可以定义它如下：

If you only want it to be public when referenced through your interface, then you can define it as such:

public class B : someI
{
    void someI.doYourWork()
    {
        //...
    }
}

你最终会得到这个结果：

And you end up with this:

var b = new B();
b.doYourWork(); // Not accessible
((someI)b).doYourWork(); // Accessible

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