如何在python中为一个类动态创建类方法 [英] How can I dynamically create class methods for a class in python
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问题描述
如果我定义一个小的python程序为
If I define a little python program as
class a():
def _func(self):
return "asdf"
# Not sure what to resplace __init__ with so that a.func will return asdf
def __init__(self, *args, **kwargs):
setattr(self, 'func', classmethod(self._func))
if __name__ == "__main__":
a.func
我收到追踪错误
Traceback (most recent call last):
File "setattr_static.py", line 9, in <module>
a.func
AttributeError: class a has no attribute 'func'
我想要弄清楚的是,我怎么能动态设置一个类方法而不实例化一个对象?
What I am trying to figure out is, how can I dynamically set a class method to a class without instantiating an object?
这个问题的答案是
class a():
pass
def func(cls, some_other_argument):
return some_other_argument
setattr(a, 'func', classmethod(func))
if __name__ == "__main__":
print(a.func)
print(a.func("asdf"))
返回以下输出
<bound method type.func of <class '__main__.a'>>
asdf
推荐答案
可以动态添加类方法通过类对象的简单赋值或通过类对象的setattr赋值给类。这里我使用python约定,类以大写字母开头,以减少混淆:
You can dynamically add a classmethod to a class by simple assignment to the class object or by setattr on the class object. Here I'm using the python convention that classes start with capital letters to reduce confusion:
# define a class object (your class may be more complicated than this...)
class A(object):
pass
# a class method takes the class object as its first variable
def func(cls):
print 'I am a class method'
# you can just add it to the class if you already know the name you want to use
A.func = classmethod(func)
# or you can auto-generate the name and set it this way
the_name = 'other_func'
setattr(A, the_name, classmethod(func))
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