获取类的泛型 [英] Get class of generic

问题描述

我的课程以

public abstract class LastActionHero<H extends Hero>(){

现在代码中我想写 H.class 可能（像 String.class 或 Integer.class 是）。

Now somewhere in the code I want to write H.class but that isn't possible (like String.class or Integer.class is).

你能告诉我如何获得通用的 Class 吗？

Can you tell me how I can get the Class of the generic?

推荐答案

您可以动态提供类型，但编译器不会自动执行此操作。

You can provide the type dynamically, however the compiler doesn't do this for you automagically.

public abstract class LastActionHero<H extends Hero>(){
    protected final Class<H> hClass;
    protected LastActionHero(Class<H> hClass) {
        this.hClass = hClass;
    }
    // use hClass how you like.
}

BTW：这不是不可能动态获得，用来。例如

BTW: It not impossible to get this dynamically, but it depends on how it is used. e.g

public class Arnie extends LastActionHero<MuscleHero> { }

可以确定Arnie.class有一个带有Generic参数MuscleHero

It is possible to determine that Arnie.class has a super class with a Generic parameter of MuscleHero.

public class Arnie<H extend Hero> extends LastActionHero<H> { }

超类的泛型参数将只是 H 在这种情况下。

The generic parameter of the super class will be just H in this case.

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