致命错误：函数名称必须是一个字符串。PHP错误 [英] Fatal error: Function name must be a string in.. PHP error

问题描述

您好我有一个名为User的类和一个名为insertUser（）的方法。

Hi I have a class called User and a method called insertUser().

function insertUser($first_name, $last_name, $user_name, $password, $email_address, $group_house_id)
  {
    $first_name = mysql_real_escape_string($first_name);
    $last_name = mysql_real_escape_string($last_name);
    $user_name = mysql_real_escape_string($user_name);
    $password = mysql_real_escape_string($password);
    $email_address = mysql_real_escape_string($email_address);

    $query = "INSERT INTO Users
              (FirstName,LastName,UserName,Password,EmailAddress, GroupHouseID) VALUES
              ('$first_name','$last_name','$user_name','$password','$email_address','$group_house_id')";
    $mysql_query($query);
  }

我这样调用：

$newUser = new User();
$newUser->insertUser($first_name, $last_name, $user_name, $email, $password,          $group_house_id);

当我运行代码时，我得到这个错误：

When I run the code I get this error:

Fatal error: Function name must be a string in /Library/WebServer/Documents/ORIOnline/includes/class_lib.php on line 33

任何人都知道我在做什么？此外，这是我第一次尝试OO PHP。

Anyone know what I am doing wronly? Also, this is my first attempt at OO PHP.

干杯，

Jonesy

推荐答案

$ mysql_query（$ query）; => mysql_query查询）; 。注意丢失的美元。如果尝试对变量使用函数调用语法，它将查找具有由变量值给定的名称的函数。在这种情况下，你没有一个 mysql_query 变量，所以它回来没有什么，这不是一个字符串，因此给你的错误。

$mysql_query($query); => mysql_query($query);. Note the missing dollar. If you try to use function call syntax on a variable, it looks for a function with the name given by the value of the variable. In this case, you don't have a mysql_query variable, so it comes back with nothing, which isn't a string, and thus gives you the error.

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