NameError在python中使用execfile [英] NameError using execfile in python
问题描述
我的应用程序有一个按钮,可以使用 execfile 动态地执行python脚本。如果我在脚本中定义了一个函数(例如。 spam()),并尝试在另一个函数中使用该函数:
NameError:未定义全局名称spam未定义
在 eggs()中调用 spam()函数的正确方法是什么?
#mainprogram.py
class mainprogram():
def runme(self):
execfile myscript.py)
>>> this = mainprogram()
>>>> this.runme()
#myscript.py
def spam():
printspam
def eggs b spam()
egg()
似乎能够从我的主应用程序在脚本中执行一个方法。
#mainprogram.py
class mainprogram():
def on_cmdRunScript_mouseClick(self,event):
execfile(my2ndscript.py)
def bleh():
printbleh
#my2ndscript.py
bleh $ b
错误是:
NameError:name'bleh'未定义
EDIT : / p>
在第二种情况下,您将需要 import
mainprogram.py
在您的 $ PYTHONPATH
)
#mainprogram.py
class mainprogram:
def runme(self):
execfile(my2ndscript.py)
def bleh(self):
print如果__name__ =='__main__':
mainprogram()。runme()
#my2ndscript.py
import mainprogram
x = mainprogram。 mainprogram()
x.bleh()
c $ c> mainprogram 。或者更好:
#mainprogram.py
class mainprogram:
def runme b $ b execfile(my2ndscript.py,globals = {'this':self})
def bleh(self):
printbleh
if __name__ =='__main__' :
mainprogram()。runme()
#my2ndscript.py
this.bleh()
我猜想 execfile
对你的问题不是正确的解决方案。
为什么不使用 import
或 __ import __
(和 reload
,如果脚本可能会在这些点击之间变化)。
#mainprogram.py
import my2ndscript
class mainprogram:
def runme(self):
reload(my2ndscript)
my2ndscript.main(self)
def bleh
printbleh
如果__name__ =='__main__':
mainprogram()。runme()
#my2ndscript.py
def main(程序):
program.bleh()
My application has a button to execute a python script dynamically using execfile. If I define a function inside the script (eg. spam()) and try to use that function inside another function (eg. eggs()), I get this error:
NameError: global name 'spam' is not defined
What is the correct way to call the spam() function from within eggs()?
#mainprogram.py
class mainprogram():
def runme(self):
execfile("myscript.py")
>>> this = mainprogram()
>>> this.runme()
# myscript.py
def spam():
print "spam"
def eggs():
spam()
eggs()
Also, I can't seem to be able to execute a method from my main application in the script. i.e.
#mainprogram.py
class mainprogram():
def on_cmdRunScript_mouseClick( self, event ):
execfile("my2ndscript.py")
def bleh():
print "bleh"
#my2ndscript.py
bleh()
The error is:
NameError: name 'bleh' is not defined
What is the correct way to call bleh() from my2ndscript.py?
EDIT: Updated first issue
In the second case you will need import
(not sure whether "mainprogram.py"
is on your $PYTHONPATH
)
#mainprogram.py
class mainprogram:
def runme(self):
execfile("my2ndscript.py")
def bleh(self):
print "bleh"
if __name__ == '__main__':
mainprogram().runme()
#my2ndscript.py
import mainprogram
x = mainprogram.mainprogram()
x.bleh()
but this will craete second instance of mainprogram
. Or better yet:
#mainprogram.py
class mainprogram:
def runme(self):
execfile("my2ndscript.py", globals={'this': self})
def bleh(self):
print "bleh"
if __name__ == '__main__':
mainprogram().runme()
#my2ndscript.py
this.bleh()
I guess that execfile
is not right solution for your problem anyway.
Why don't you use import
or __import__
(and reload()
in case script may change between those clicks).
#mainprogram.py
import my2ndscript
class mainprogram:
def runme(self):
reload(my2ndscript)
my2ndscript.main(self)
def bleh(self):
print "bleh"
if __name__ == '__main__':
mainprogram().runme()
#my2ndscript.py
def main(program):
program.bleh()
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