C＃Object构造函数 - 速记属性语法 [英] C# Object Constructor - shorthand property syntax

问题描述

几个月前，我阅读了一个技术，如果有参数传递匹配的局部变量，那么你可以使用一些短手法来设置它们。要避免此问题：

A few months ago i read about a technique so that if there paramaters you passed in matched the local variables then you could use some short hand syntax to set them. To avoid this:

public string Method(p1, p2, p3)
{
    this.p1 = p1;
    this.p2 = p2;
    this.p3 = p3;
}

任何想法？

推荐答案

你可能在想C＃3.0中的新对象初始化语法。它看起来像这样：

You may be thinking about the new object initializer syntax in C# 3.0. It looks like this:

var foo = new Foo { Bar = 1, Fizz = "hello" };

这就是给我们一个Foo的新实例，Bar属性初始化为1， Fizz属性为hello。

So that's giving us a new instance of Foo, with the "Bar" property initialized to 1 and the "Fizz" property to "hello".

这个语法的诀窍是，如果你省略=并提供一个标识符，重新分配给同名的属性。例如，如果我已经有一个Foo实例，我可以这样做：

The trick with this syntax is that if you leave out the "=" and supply an identifier, it will assume that you're assigning to a property of the same name. So, for example, if I already had a Foo instance, I could do this:

var foo2 = new Foo { foo1.Bar, foo1.Fizz };

这样就变得非常接近你的例子了。如果你的类有p1，p2和p3属性，并且你有同名的变量，你可以这样写：

This, then, is getting pretty close to your example. If your class has p1, p2 and p3 properties, and you have variables with the same name, you could write:

var foo = new Foo { p1, p2, p3 };

请注意，这仅用于构建实例 - 不是将参数传递到方法中它可能不是你想的。

Note that this is for constructing instances only - not for passing parameters into methods as your example shows - so it may not be what you're thinking of.

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