“+” Java类的运算符 [英] "+" operator for Java-classes

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本文介绍了“+” Java类的运算符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这样的类:

 私人静态类Num {
private int val;

public Num(int val){
this.val = val;
}
}

可以添加到类的对象使用+运算符?

  Num a = new Num(18); 
Num b = new Num(26);
Num c = a + b;


解决方案

不, + 仅对数字,字符和 String 重载,并且不允许定义任何额外的重载。 p>

有一个特殊情况,当你可以连接任何对象的字符串表示 - 如果在 String 前两个操作数 toString()在所有其他对象上调用。





  int i = 0; 
String s =s;
Object o = new Object();
Foo foo = new Foo();

int r = i + i; // allowed
char c ='c'+'c'; // allowed
String s2 = s + s; // allowed
Object o2 = o + o; //不允许
Foo foo = foo + foo; //不允许
String s3 = s + o; //允许,调用o.toString()并使用StringBuilder
String s4 = s + o + foo; // allowed
String s5 = o + foo; //不允许 - 没有字符串操作数


I have a class like this:

private static class Num {
    private int val;

    public Num(int val) {
        this.val = val;
    }
}

Is it possible to add to objects of the class by using the "+"-operator?

Num a = new Num(18);
Num b = new Num(26);
Num c = a + b;

解决方案

No, you can't. + is overloaded only for numbers, chars and String, and you are not allowed to define any additional overloadings.

There is one special case, when you can concatenate any objects' string representation - if there is a String object in the first two operands, toString() is called on all other objects.

Here's an illustration:

int i = 0;
String s = "s";
Object o = new Object();
Foo foo = new Foo();

int r = i + i; // allowed
char c = 'c' + 'c'; // allowed
String s2 = s + s; // allowed
Object o2 = o + o; // NOT allowed
Foo foo = foo + foo; // NOT allowed
String s3 = s + o; // allowed, invokes o.toString() and uses StringBuilder
String s4 = s + o + foo; // allowed
String s5 = o + foo; // NOT allowed - there's no string operand

这篇关于“+” Java类的运算符的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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