PHP，区分内部和外部类方法调用 [英] PHP, distinguish between internal and external class method call

问题描述

不能让我的头，这是，有什么方法来检查一个方法是否在内部调用？我的意思是一个回溯，检查它是否被$ this调用，而不是一个指向实例的指针。类似私人功能的概念，但只有功能是公共的？

Can't get my head around this, is there any way to check if a method was called internally? By this I mean a traceback to check if it was called by $this and not a pointer to the instance. Kind of like the concept of private function but only function is public?

<?php

class Foo {
    public function check () {
        /*
        if invoked by $this (internally)
            return true
        else
            return false
        */
    }

    public function callCheck () {
        /* returns true because its called by $this */
        return $this->check();
    }
}

$bar = new Foo;
// this should return false because we are calling it from an instance
$bar->check();
// where as this will return true
$bar->callCheck();

?>

也许这是可撤销的，但是我真的需要它在我的大学项目吗？任何人遇到解决方案或知道如何识别解决方案。

Maybe this is undo-able but I really need it for my project at university? Anyone come across a solution or knows how I would identify a solution.

谢谢。

推荐答案

以下解决方案无效。

您可以使用 debug_backtrace 但它会很慢。我真的建议你找到一个不同的方法来解决你想克服的问题。

You could use debug_backtrace but it will be slow. I really advise you find a different way to solve the problem you are trying to overcome.

<?php
public function check() {
    $trace = debug_backtrace();
    if ($trace[1]['class'] == 'MyClassName') {
        return true;
    }
    return false;
}

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