Python极其动态的类属性 [英] Python extremely dynamic class properties

问题描述

要在类中创建属性，只需执行 self.property = value 。我想能够让这个类中的属性完全依赖于一个参数。让我们调用 Foo 的实例 Foo 。

c>类将获取元组的列表：

  l = [（first，foo）， ，bar），（anything，you get the point）] 
 bar = Foo（l）
  

现在，分配给 bar 的 Foo 类的实例将具有以下属性：

  bar.first 
 #foo 
 bar.second 
 #bar 
 bar.anything 
＃你得到点
  

可能？如何？

解决方案

这些称为属性，而不是 / em>。记住这一点，方法 setattr（） 变得更明显：

  class Foo（object）：
 def __init __ ，l）：
 for k，v in l：
 setattr（self，k，v）
  

b $ b

这会获取 l 中的每个键值对，并在新实例上设置属性 k Foo （ self ）至 v >

使用您的示例：

  l = [（first，foo ），（second，bar），（anything，你得到点）] 
 bar = Foo（l）
 
打印bar.first 
 #foo 
 print bar.second 
 #bar 
 print bar.anything 
＃获得点数
  

To create a property in a class you simply do self.property = value. I want to be able to have the properties in this class completely dependent on a parameter. Let us call this class Foo.

instances of the Foo class would take a list of tuples:

l = [("first","foo"),("second","bar"),("anything","you get the point")]
bar = Foo(l)

now the instance of the Foo class we assigned to bar would have the following properties:

bar.first
#foo
bar.second
#bar
bar.anything
#you get the point

Is this even remotely possible? How?

解决方案

These are called attributes, rather than properties. With that in mind, the method setattr() becomes more obvious:

class Foo(object):
    def __init__(self, l):
        for k, v in l:
            setattr(self, k, v)

This takes each key-value pair in l and sets the attribute k on the new instance of Foo (self) to v.

Using your example:

l = [("first","foo"),("second","bar"),("anything","you get the point")]
bar = Foo(l)

print bar.first
#foo
print bar.second
#bar
print bar.anything
#you get the point

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