PHP - 检查命名空间内是否存在全局类 [英] PHP - Check if global class exists inside namespace

问题描述

如果你在另一个类的命名空间内，你如何检查一个全局类是否存在class_exists？例如：

How can you check if a global class exists with class_exists if you are inside the namespace of another class? For example:

<?php
namespace Rvdv\Test\Example;

class ExampleClass
{
    public function testNamespace()
    {
        // This says that it doesn't exists :(
        print class_exists('\\Test');
    }
}

其中类是一个全局定义的类。

Where class is a global defined class.

推荐答案

你不得不在你的其他问题，测试不在这个范围内声明（你忘了include吗？）我测试了这样：

You've had to screw up something in your other issues - most likely the class test is not declared in this scope (did you forget include?). I tested this thusly:

phpcltest2.php：

phpcltest2.php:

<?php
class Test { }

$ b b

phpcltest.php：

phpcltest.php:

<?php
namespace Rvdv\Test\Example;
require 'phpcltest2.php';

class ExampleClass
{
    public function testNamespace()
    {
    print class_exists('\\Test');
    }
}

$nc = new ExampleClass();
$nc->testNamespace();

结果是预期的：它打印出1。因此，请检查您的包含路径。

The results were expected: it prints out "1". So check your include paths.

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