将字符串元素转换为类属性（py 2.7） [英] Convert string elements to class attributes (py 2.7)

问题描述

我有一个字符串，我想使用元素将它们转换为类的attrs。

i have a string, and i want to use the elements to convert them into attrs of a class.

@staticmethod
def impWords():
    #re

    tempFile = open('import.txt','r+')
    tempFile1 = re.findall(r'\w+', tempFile.read())

    for i in range(len(tempFile1)):
        new=word(word.id=i,word.data=str(tempFile1[i]), word.points=int(tempFile1[i]+1))
        Repo.words.append(word)
    print str(Repo.words)

下面的错误弹出，我怎么可以修复这我试过一些想法，但已经没有成功。

the following error pops up, how can i repair this i tried some ideas i had but it didnt worked out.

File "D:\info\F P\Lab\lab5.7\Scramble\Repository\Rep.py", line 82, in impWords
new=word(id=int(i),data=str(tempFile1[i]), points=int(tempFile1[i]+1))
TypeError: cannot concatenate 'str' and 'int' objects

推荐答案

：

int(tempFile1[i]+1)

您的 tmpFile [i] 是一个字符串。您不能将整数 1 添加到字符串。您可以尝试将字符串转换为整数，然后添加：

Your tmpFile[i] is a string. You cannot add the integer 1 to a string. You can try to convert your string into an integer and add the one afterwards:

int(tempFile1[i])+1

所以整行看起来像这样：

So the whole line looks like this:

new=word(word.id=i,word.data=str(tempFile1[i]), word.points=int(tempFile1[i])+1)

更新：无论如何，这可能不会工作。考虑这个选择（你必须正确定义单词类）：

UPDATE: Anyway, this is probably not going to work. Consider this alternative (you have to define the word-class properly):

@staticmethod
def impWords():
    with open('import.txt','r+') as f:
        for i, word in enumerate(re.findall(r'\w+', f.read())):
            Repo.words.append(word(id=i, data=word, points = int(word)+1))

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