使< li>包括使用PHP和CSS [英] Make <li> active with includes using PHP and CSS
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问题描述
我使用这些文件作为我的网站的基础：
I use these files as base for my website:
menu.php ：
$p = $_GET['p'];
switch($p)
{
case "home":
$p = "page/home.php";
break;
case "customers":
$p = "page/customers.php";
break;
default:
$p = "page/home.php";
break;
}
<ul id='nav'>
<li>Title</li>
<ul>
<li class="nav active"><a href="?p=home">Home</a></li>
<li><a href="?p=customers">Customers</a></li>
</ul>
</ul>
default.php ：
<body>
<div id='navcontainer'>
<?php include ("menu.php"); ?>
</div>
<div id='content'>
<?php include ($p); ?>
</div>
style.css ：
#navcontainer {margin:0; padding:0; width:220px;float:left;}
#nav li {background:#36393D; color:#fff; padding:5px 3px 5px 20px; margin:4px;border-left:5px solid #3F4C6B;}
#nav ul li{display:block; padding:3px; background:#fff; color:#000;border:none; padding:3px 0 3px 30px;}
#nav ul li:hover, #nav ul li.active {background:#eee; cursor:pointer; border-left:5px solid #4096EE;padding:3px 0 3px 25px;}
#nav ul li a {text-decoration:none; color:#000;}
home.php 和所有网页：
<p>Hello world!</p>
我想知道是否可以得到我的 menu.php 在< li> 项目上根据当前访问的页面将类切换到 nav active 。
I wonder if it is possible to get my menu.php to switch class to nav activeon the <li> items based on what page is currently visited.
任何想法？
推荐答案
创建一个额外的变量
<?php
$p = $_GET['p'];
$currentPageId = 0;
switch($p)
{
case "home":
$p = "page/home.php";
$currentPageId = 1;
break;
case "customers":
$p = "page/customers.php";
$currentPageId = 2;
break;
default:
$p = "page/home.php";
$currentPageId = 1;
break;
}
?>
<ul id='nav'>
<li>Title</li>
<ul>
<li <?php if($currentPageId == 1) { echo 'class="nav active"'; } ?> ><a href="?p=home">Home</a></li>
<li <?php if($currentPageId == 2) { echo 'class="nav active"'; } ?> ><a href="?p=customers">Customers</a></li>
</ul>
</ul>
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