为什么我的代码出来的错误的输出？是我的insert类错了吗？ [英] Why is my code coming out with the wrong output? Is my insert class wrong?

问题描述

我必须创建类，以实现与主类别的人有一些原因，由于某种原因，我没有得到正确的输出，我不知道是我的计算，我不认为他们是或我insert type is wrong。

I have to create classes to be implemented with the main class someone else has and for some reason I am not getting the right outputs, I'm not sure is my calculations are off which I don't think they are or my insert class is wrong.

预期输出：

Median = 44.5

Median = 44.5

平均= 49.300

Mean = 49.300

SD = 30.581

SD = 30.581

实际输出：

中位数= 0.0

平均= 0.967

SD = 4.712

SD = 4.712

public class StatPackage { 
int count; 
double [] scores; 
final int MAX = 500; 


StatPackage() { 
count = 0; 
scores = new double[MAX]; 
} 
public void insert (double value) { 
if (count < MAX){ 
scores[count] = value; 
++ count; 
} 
} 
public double Mean () { 
    double sum = 0; 
    //For loop for calculating average or mean
    for(int i = 0; i < scores.length; i++){
            sum += (scores[i]);
            count++;    
    }
    double average = sum/count;  
    return average;
    } 

public double Median() { 
int min; 
int tmp; 
int size; 

for (int i = 0; i < scores.length - 1; i ++) 
{ 
min = i; 
for (int pos = i + 1; pos < scores.length; pos ++) 
if (scores [pos] < scores [min]) 
min = pos; 

tmp = (int)scores [min]; 
scores [min] = scores [i]; 
scores [i] = tmp; 

} 
double median = 0;
if  (scores.length % 2 == 0){
    median = (scores[scores.length/2-1] + scores[scores.length/2])/2;
}
else {
    median = (scores[((scores.length/2))]);
}
return median;
} 

public double Variance () { 
    double variance = 0;
    double sum = 0;
    //For loop for getting the variance
    for(int i = 0; i < scores.length; i++){
        sum += scores[i];
        variance += scores[i] * scores[i];
        count++;
    }
    double varianceFinal = ((variance/count)-(sum*sum)/(count*count));
    return (varianceFinal);
} 

public double StdDev (double variance) { 
    double sum = 0;
    for(int i = 0; i < scores.length; i++){
        sum += scores[i];
        variance += scores[i] * scores[i];
        count++;
    }
    double varianceFinal = ((variance/count)-(sum*sum)/(count*count));
return Math.sqrt(varianceFinal);

}

}   

推荐答案

因为解决方案很容易通过调试找到，我只会给你一个提示：

Because the solution is easily found by debugging, I will only give you a hint:

$ c> mean of 3，4 and 5 is 4：（3 + 4 + 5）/ 3 ，not （3 + 4 + 5）/（n * 3）其中
n 是正整数。 $ b

The mean of 3, 4 and 5 is 4: (3+4+5)/3, not (3+4+5)/(n*3) where n is a positive integer.

如果你看看你的意思和std并除以预期结果，你会看到它是一个四舍五入的数字。

If you look at your mean and std and divide it by the expected result, you will see it's a rounded number.

一旦找到1个问题的解决方案，您就会马上知道为什么其他结果也是错误的）=）

Once you find the solution to 1 problem, you will immediately know why the other results are faulty as well =)

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