Jquery单击弹出和Cookie（显示弹出窗口一次） [英] Jquery Click Popup and cookies (Show popup once)

问题描述

载入Jquery

    <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
    <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.10.3/jquery-ui.min.js"></script>

我试图获得一个弹出式窗口只加载一次，然后不再显示另外31天。

I'm trying to get a popup to only load once then not show again for another 31 days.

    <script type="text/javascript"><!--
    jQuery(document).ready(function()
    {
if (jQuery.cookie('test_status') != '1')
{
    setTimeout(function()
    {
        jQuery('.lightbox-handle').reveal()
        jQuery('.lightbox-handle').click();
        jQuery.cookie('test_status', '1', { expires: 31}); 
    }, 1000);
}
    });
    //--></script>

推荐答案

您是否包含jQuery Cookie插件， https://github.com/carhartl/jquery-cookie 。您可以在CDNJS的 http：/ /cdnjs.cloudflare.com/ajax/libs/jquery-cookie/1.3.1/jquery.cookie.min.js

Are you including the jQuery cookie plugin, https://github.com/carhartl/jquery-cookie. You can find on CDNJS at http://cdnjs.cloudflare.com/ajax/libs/jquery-cookie/1.3.1/jquery.cookie.min.js

<script type="text/javascript"
        src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript"
        src="//cdnjs.cloudflare.com/ajax/libs/jquery-cookie/1.3.1/jquery.cookie.min.js"></script>
<script type="text/javascript">
    $(function() {
        if ($.cookie('test_status') != '1')
        {
            setTimeout(function()
            {
                alert('foo');
                jQuery.cookie('test_status', '1', { expires: 31}); 
            }, 1000);
        }
    }
</script>

适用于此小提琴 http://jsfiddle.net/WyYZ8/

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