python闭包+ oop [英] python closure + oop

问题描述

我试图做一些有点奇怪（至少对我）与python关闭。说我有这样的2个类：

I'm trying to do something a bit strange (at least to me) with python closure. Say I have 2 classes like this:

#!/usr/bin/python
import types

def method_a(self):
    print "ma %d" % self.val

class A(object):
    def __init__(self):
        self.val = 5
        pass

    def foo(self, a):
        def closure(self):
            print "closure %d, %d" % (self.val, a)
        return closure

class B(object):
    def __init__(self):
        self.val = 10
        pass

    def foo(self):
        print "B::foo %d"  % self.val


a = A()
b = B()
b.undo = types.MethodType(a.foo(1), b)

b.undo()

因此，对象a的方法返回一个要被对象b使用的闭包，而闭包函数将绑定到对象b，在：

So object a's method returns a closure to be used by object b and the closure function will be bound to object b as the above code will result in:

closure 10, 1

我的问题是：是否还有允许closure（）方法访问对象的属性，方法a？

My question is: is there anyway to allow the closure() method to access attribute, method of object a?

/ p>

Thanks,

推荐答案

给内部的另一个名字：

def foo(self, a):
    def closuer(b):
        print "closure %d, %d" % (self.val, a)
    return closuer

另外，而不是使用types.MethodType，你可能想使用functools.partial

Also, rather then using types.MethodType, you might want to use functools.partial

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