BAD_INSTRUCTION在swift闭包 [英] BAD_INSTRUCTION within swift closure
问题描述
func loadMe() -> Void {
println(me.initUrl());
let url:NSURL = NSURL(string:me.initUrl())
let request:NSURLRequest = NSURLRequest(URL:url)
let queue:NSOperationQueue = NSOperationQueue()
NSURLConnection.sendAsynchronousRequest(request, queue:queue, completionHandler:{response, data, error in
if data {
var jerr:NSError?
var json:NSDictionary = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error:&jerr) as NSDictionary
if !jerr {
println(json.description)
let time:String = json.valueForKey("time") as String
println(time)
// self.me.setDictionary(json)
}
}
})
}
上面的代码工作正常,想要将值从NSDictionary分配给变量。
The code above works fine up to the point where i want to assign a value from an NSDictionary to a variable.
let time:String = json.valueForKey("time") as String
后跟EXC_BAD_INSTRUCTION(代码= EXC_I386_INVOP,子代码= 0x0),但
is followed by EXC_BAD_INSTRUCTION(code=EXC_I386_INVOP,subcode=0x0) but
println(json.description)
打印出一个有效的NSDictionary。有没有人知道这个问题的解决方案?
prints out a valid NSDictionary. Does anybody know a solution to this problem?
推荐答案
我解决了我的问题,转换到正确的类型的原始NSDictionary值后我意识到不是NSDictionary的所有值都是NSStrings。如果您的服务返回类似于此的混合类型JSON对象
I solved my problem with casting to the correct type of the original NSDictionary value after i realised that not all values of the NSDictionary were NSStrings. If your service returns a mixed type JSON object like this
{"id":2, "name":"AC Vent Temp", ...}
你必须获取这样的值。
var id:int = sensor.valueForKey("id") as Int;
var name:String? = sensor.valueForKey("name") as String;
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