cmd脚本中的日期算术 [英] Date arithmetic in cmd scripting

问题描述

我需要编写一个脚本，将文件名从aDate.txt更改为bDate.txt，其中：

I need to write a script to change a filename from aDate.txt to bDate.txt where:

• aDate是当前系统日期格式为 yyyymmdd 格式


• bDate是当前系统日期 - 格式为

• aDate is the current system date in yyyymmdd format and
• bDate is the current system date - 1 in yyyymmdd format.

我目前有：

set yy=%date:~6,2%
set mm=%date:~3,2%
set dd=%date:~0,2%
if "%date:~6,1%"==" " set yy=0%yy:~1,1%
if "%date:~3,1%"==" " set mm=0%mm:~1,1%
if "%date:~0,1%"==" " set dd=0%dd:~1,1%
SET sys_date=20%yy%%mm%%dd%
ECHO %sys_date%
REM still have to do this bit properly
SET sys_date_yesterday=%sys_date%a
move %sys_date%.txt %sys_date_yesterday%.txt

但我不知道如何做日期-1的事情（除了长风）从一天减去1，如果是= 0

but I have no idea how to do the date -1 thing (other than the long winded) subtract 1 from the day and if that is = 0 then subtract one from the month and set the day = to the last day of the new month and so on for years.

任何想法？

推荐答案

这也有效：

http://www.robvanderwoude.com/datetiment.php#Yesterday

它是非常完整的，它检查注册表的本地日期格式设置，并使用那些在创建昨天的日期。

It is very complete in that it checks the registry for local date format settings and uses those when creating the yesterday date.

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