查找字母更改为差异字母的所有发生 [英] Find ALL Ocurences of Letter change to Diffrent Letter

问题描述

我正在开发一种加密方法，将所有字母改为一个数字字符串。例如：

I am working on a encryption method that changes all letters to a string of numbers an Example Follows:

set a=a
set b=b
set c=c
set aa=543241254
set bb=785214185
set cc=842501445

我的问题是如何扫描用户输入的文件，并将所有字母改为数字。 （正在更改文件的文件类似于 hihowareyou 没有空格或大写）
我试图在所述文件中搜索'a'

My issue is How can I scan a file entered by the user and change all letters to the numbers. (The File being changed text is like "hihowareyou" No spaces or capitals) What I tried was to search for an 'a' in said file and replace it with the numbers but my section did not work.

(for /f "delims=" %%i in ('findstr /n "^" "%textfile%"') do (
    set "line=%%i"
    setlocal enabledelayedexpansion
    set "line=!line:%b%=%bb%!"
    echo(!line!
    endlocal
))>"%newfile%"
type "%newfile%" >>%newfile%

我不知道如何扫描文本文件中的字母，并用％a％，％b ％，％c％等。

I am not sure what to do to scan for the letter in the text file and replace it with %a%,%b%,%c% etc.

推荐答案

你应该首先意识到这些命令：

You should realize at first that these commands:

set a=a
set b=b
set c=c

...根据定义是无用的（即没有进一步解释），虽然很明显，在这种情况下写％ a％将始终与写入 a 相同（对于其余字母也是如此）。

... are useless "by definition" (that is, with no further explanation), although it should be evident that in this case writting %a% will always be the same than writting just a (the same happen for the rest of letters).

如果您想用一串数字来更改一个字母，那么正确的方式应该是：

If you want to change one letter by a string of numbers, then the right way should be this:

set a=543241254
set b=785214185
set c=842501445

然后，为了通过变量的内容更改a字符，您可以在 命令：

Then, in order to change the 'a' letter by the contents of a variable, you may do something like this inside your for command:

set "line=!line:a=%a%!"

再次：改变 a

Again: this change the a letter by the contents of a variable.

现在，应该意识到，您需要执行先前的替换，而不是在单个 a 字母/变量上，而是在一个系列变量信。以相同的方式（实际上意味着使用相同的代码）处理一系列变量的标准方法是通过命令将下标的值与 数组 。例如，如果我们为数组的名称选择字母并在数组的不同元素中定义所需的替换值，那么我们肯定会这样做：

Now, you should realize that you need to perform the previous replacement not on the single a letter/variable, but on a series of variables represented each one by one letter. The standard way to process a series of variables in the same way (that really means "using the same code") is via a for command that vary the value of a subscript in combination with an array. For example, if we choose "letter" for the name of the array and define the desired replacement values in different elements of the array, surely we do something like this:

set letter[a]=543241254
set letter[b]=785214185
set letter[c]=842501445

之后，我们只需要知道这些变量/值是如何被操作的。有关这一点的详细信息，请参阅 cmd.exe（批处理）脚本中的数组，链接列表和其他数据结构，因此我不会在这里重复。但是，解决这个问题所需的数组管理比在该链接上给出的完整解释更简单。

After this, we just need to know how these variables/values may be manipulated. Full details on this point are given at Arrays, linked lists and other data structures in cmd.exe (batch) script, so I will not repeat they here again. However, the array management required to solve this problem is simpler than the full explanation given at that link.

如果执行此命令： set letter ，将显示以letter开头的所有变量，包括其值;例如：

If you execute this command: set letter, all the variables that start with "letter" will be shown, including their values; for example:

letter[a]=543241254
letter[b]=785214185
letter[c]=842501445

如果我们对/ Ftokens = 2使用 3 delims = [] =%% a in（'set letter'）do ... 命令，那么 %% a 将包含数组的每个下标，即字母 a ， b ， c 等，并且 %% b 参数将包含相应的数字值。

If we use a for /F "tokens=2,3 delims=[]=" %%a in ('set letter') do ... command, then the %%a replaceable parameter will contain each one of the subscripts of the array, that is, the letters a, b, c, etc., and the %%b parameter will contain the corresponding numeric values.

这样，为了完成你的程序和替换所有定义的字母，你只需要放置 setline =！line：％b％=％bb％！ code>命令中的行正确地改变％b％部分，代表 ， %% a ;并用 %% b 数值的％bb％ >：

This way, in order to complete your program and replace all defined letters, you just need to place your set "line=!line:%b%=%bb%!" line inside previous for command and correctly change the %b% part, that represent the letter, by %%a; and replace the %bb% part, that represent the numeric value, by %%b:

for /F "tokens=2,3 delims=[]=" %%a in ('set letter') do (
   set "line=!line:%%a=%%b!"
)

当然，您还必须在程序开始时定义字母数组...

Of course, you must also define the letter array at beginning of the program...

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