如何在Objective-C中执行字符串转换？ [英] How to do string conversions in Objective-C?

问题描述

我想将一个字符串转换为双精度，并在做一些数学后，将其转换回一个字符串。

如何在Objective-

解决方案

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可以使用

将NSString转换为双精度。

  double myDouble = [myString doubleValue]; 
 

舍入到最接近的整数可以做为

  int myInt =（int）（myDouble +（myDouble> 0？0.5：-0.5））
  

我真的不知道是否有更精简的方式转换回

字符串

  NSString * myNewString = [NSString stringWithFormat：@％d，myInt]; 
  

I want to convert a string into a double and after doing some math on it, convert it back to a string.

How do I do this in Objective-C?

Is there a way to round a double to the nearest integer too?

解决方案

You can convert an NSString into a double with

double myDouble = [myString doubleValue];

Rounding to the nearest int can then be done as

int myInt = (int)(myDouble + (myDouble>0 ? 0.5 : -0.5))

I'm honestly not sure if there's a more streamlined way to convert back into a string than

NSString* myNewString = [NSString stringWithFormat:@"%d", myInt];

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