从NSMutableArray中删除重复项 [英] Removing duplicates from NSMutableArray

问题描述

我有从数组中删除重复的对象的这个问题。
我试过这些：

I have this problem with removing duplicate objects from an array. I tried these already:

noDuplicates = _personalHistory.personalHistory;

for (int i=[noDuplicates count]-1; i>0; i--) {
    if ([noDuplicates indexOfObject: [noDuplicates objectAtIndex: i]]<i)
        [noDuplicates removeObjectAtIndex: i];
}


for (PersonalHistory_artikels *e in _personalHistory.personalHistory) {
    if (![noDuplicates containsObject:e]) {
        NSLog(@"Dubplicates");
        [noDuplicates addObject:e];
    }
}


for (i=0; i<_personalHistory.personalHistory.count; i++) {
    PersonalHistory_artikels *test = [_personalHistory.personalHistory objectAtIndex:i];
    for (j=0; j<_personalHistory.personalHistory.count; j++) {
        PersonalHistory_artikels *test2 = [_personalHistory.personalHistory objectAtIndex:j];
        if (! [test.nieuwsTITLE_personal isEqual:test2.nieuwsTITLE_personal]) {
            NSLog(@"Add test = %@", test.nieuwsTITLE_personal);
            [noDuplicates addObject:test];
        }
    }
}

我正确的数组。最后一个是最好的，但它仍然显示重复的值。有人可以帮我解决这个问题吗？
非常感谢。

But none of the above gave me the right array. The last one was the best, but it still showed duplicate values. Can someone help me with this problem? Thank you very much.

推荐答案

只需将数组转换为 NSSet

请注意，集合不具有排序顺序。因此，你可以去更便宜和放弃订单，或去一个稍微贵一点的操作，但保持订单。

Note that a set doesn't have a sorting order. Therefore, you can go cheaper and forgo the order, or go for a slightly more expensive operation but keep the order.

NSArray *hasDuplicates = /* (...) */;
NSArray *noDuplicates = [[NSSet setWithArray: hasDuplicates] allObjects];

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