使用Objective-C / Cocoa启动Mac应用程序 [英] Launching an Mac App with Objective-C/Cocoa

问题描述

当使用命令行启动Path Finder应用程序时，我使用 open -a Path Finder.app / Users / 。
基于这个想法，我使用以下代码启动Path Finder。

When launching Path Finder app with command line, I use open -a Path Finder.app /Users/. Based on this idea, I use the following code to launch Path Finder.

我可以启动应用程序而不使用 code>命令行？

Can I have launch app without using open command line?

NSTask *task;
task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/open"];

NSArray *arguments;
arguments = [NSArray arrayWithObjects: @"-a", @"Path Finder.app", @"/Users/", nil];
[task setArguments: arguments];

NSPipe *pipe;
pipe = [NSPipe pipe];
[task setStandardOutput: pipe];

NSFileHandle *file;
file = [pipe fileHandleForReading];

[task launch];

推荐答案

if(![[NSWorkspace sharedWorkspace] launchApplication:@"Path Finder"])
    NSLog(@"Path Finder failed to launch");

使用参数：

NSWorkspace *workspace = [NSWorkspace sharedWorkspace];
NSURL *url = [NSURL fileURLWithPath:[workspace fullPathForApplication:@"Path Finder"]];
//Handle url==nil
NSError *error = nil;
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[workspace launchApplicationAtURL:url options:0 configuration:[NSDictionary dictionaryWithObject:arguments forKey:NSWorkspaceLaunchConfigurationArguments] error:error];
//Handle error

您也可以使用NSTask传递参数：

You could also use NSTask to pass arguments:

NSTask *task = [[NSTask alloc] init];
NSBundle *bundle = [NSBundle bundleWithPath:[[NSWorkspace sharedWorkspace] fullPathForApplication:@"Path Finder"]]];
[task setLaunchPath:[bundle executablePath]];
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[task setArguments:arguments];
[task launch];

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