如何创建“索引” NSIndexPath所需：indexPathWithIndexes：length： [英] How to create the "indexes" required for NSIndexPath:indexPathWithIndexes:length:

问题描述

用一个或多个节点创建索引路径的类方法是：

The class method to create an index path with one or more nodes is:

+ (id)indexPathWithIndexes:(NSUInteger *)indexes length:(NSUInteger)length

如何创建第一个参数？

How do we create the "indexes" required in the first parameter?

文档将其列为组成索引路径的索引数组，但它期望有一个（NSUinteger *）。

The documentation listed it as Array of indexes to make up the index path but it is expecting a (NSUinteger *).

要创建一个1.2.3.4的索引路径，它只是一个[1,2,3,4]的数组？

To create an index path of 1.2.3.4, is it simply an array of [1,2,3,4] ?

推荐答案

您是正确的。您可以这样使用它：

You are correct. You might use it like this:

NSUInteger indexArr[] = {1,2,3,4};

NSIndexPath *indexPath = [NSIndexPath indexPathWithIndexes:indexArr length:4];

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