停止/暂停Swift应用程序的时间段 [英] Stop / Pause swift app for period of time

问题描述

我的应用程序使用多个线程 NSTimer 对象。

My app uses multiple threads of NSTimer Object.

在一个函数中（随机随机调用，不是固定的延迟），我想让它暂停整个应用程序，暂停 1秒。我有以下代码：

Within the one function (called randomly at random times, not a fixed delay) I want it to pause the whole app, pause the threads for 1 second only. I have the following code:

[self performSelector:@selector(subscribe) withObject:self afterDelay:3.0 ];

这是客观的C，我试着把它翻译成Swift：

Which is objective C, and I tried translating it into Swift like this:

self.performSelector(Selector:changeColourOfPage(), withObject: self, afterDelay: 1.0)

但我得到的错误参数'waitUntilDone'在调用缺少参数和当我把它，它说它想要参数 modes 但是当我把它放在额外的参数模式。

But I am getting the error Missing argument for parameter 'waitUntilDone' in call and when I put that in, it says it wants the argument modes but when I put that in it says Extra argument modes.

我不知道如何暂停应用程序及其所有的线程几秒钟，然后像正常一样继续？

I cannot figure out how to pause the app and all it's threads for a couple of seconds, and then carry on like normal?

任何想法？

推荐答案

performSelector方法在Swift中不可用。您可以使用dispatch_after获取延迟功能。

The performSelector methods aren't available in Swift. You can get the delay functionality by using dispatch_after.

let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(NSEC_PER_SEC * 1))
dispatch_after(delayTime, dispatch_get_main_queue()){
    changeColourOfPage() 
}

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