验证NSString中是否存在单词 [英] Verify the existence of a word in an NSString

查看:172
本文介绍了验证NSString中是否存在单词的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我搜索了一下,但找不到这个问题的答案(可能很简单)。

I searched a bit, but couldn't find an answer to this (probably very simple) question.

我有一个NSString,我想检查它是否包含一个单词。像这样:

I have an NSString, and I'd like to check if it contains a word. Something like this:

NSString *sentence = @"The quick brown fox";
NSString *word = @"quack";
if ([sentence containsWord:word]) {
    NSLog(@"Yes it does contain that word");
}

感谢。

推荐答案

以下应该可以工作:

NSString *sentence = @"The quick brown fox";
NSString *word = @"quack";
if ([sentence rangeOfString:word].location != NSNotFound) {
    NSLog(@"Yes it does contain that word");
}

它使用 rangeOfString:返回 NSRange 结构,指示单词的位置,如果找不到它 NSRange.location 将等于 NSNotFound

It uses rangeOfString: to return an NSRange structure, indicating the location of the word, if it can't find it NSRange.location will be equal to NSNotFound.

这篇关于验证NSString中是否存在单词的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆