如何获取当前选择的NSPopUpButtonCell？ [英] How to retrieve the current selection of an NSPopUpButtonCell?

问题描述

我在 NSTableView 中使用 NSPopUpButtonCell 。弹出按钮绑定到 ApplicationDelegate 提供的 NSArray 属性。当我选择弹出按钮的菜单项时，我希望检索当前选择或其索引。我添加了一个IBAction被通知，并设置了 NSMenuDelegate 。 两者都始终返回index = 0。

I am using an NSPopUpButtonCell in an NSTableView. The popup button has a binding to an NSArray property offered by the ApplicationDelegate. When I select a menu item of the popup button I expect to retrieve the current selection or its index. I added an IBAction to being informed and also set up an NSMenuDelegate. Both return index = 0 at all times.

// indexOfSelectedItem is always 0.
NSInteger indexOfSelectedItem = [m_popUpButtonCell indexOfSelectedItem];

我创建了一个示例项目。希望您能澄清一些事情。

I created an example project with the aforementioned configuration. Hopefully you can clarify things.

推荐答案

本文使用弹出式菜单实现一对一关系回答了我的问题。

我更新了示例项目。

The article Implementing To-One Relationships Using Pop-Up Menus answered my question.
I updated the example project.

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